RowQ
The Vault
RowQ
The Vault
CBSE Class 12 Maths · 11 questions · 26 marks
A matrix packages a rectangular array of numbers into a single object that can be added, scaled and multiplied under its own rules. This chapter fixes the arithmetic — especially the non-commutative product AB ≠ BA in general — and introduces the transpose, which splits every square matrix into a symmetric and a skew-symmetric part. Elementary row operations then give a mechanical way to invert a matrix without touching determinants.
If A is a matrix of order 2×3 and B is a matrix of order 3×4, then the order of AB is:
Answer
The order of AB is 2×4. Matrix multiplication is defined when the number of columns of A (3) equals the number of rows of B (3), which holds here. The resulting product takes the number of rows of A and the number of columns of B, giving order 2×4.
If A = [[2,3],[1,4]], then A' (the transpose of A) is:
Answer
A' = [[2,1],[3,4]]. The transpose is formed by turning rows into columns: the first row (2,3) becomes the first column, and the second row (1,4) becomes the second column. So A' = [[2,1],[3,4]].
For a skew-symmetric matrix A, the diagonal elements are always:
Answer
The diagonal elements are always 0. A skew-symmetric matrix satisfies A' = −A, so every entry aᵢⱼ = −aⱼᵢ. For a diagonal entry, i = j, giving aᵢᵢ = −aᵢᵢ, so 2aᵢᵢ = 0 and aᵢᵢ = 0.
If A = [[1,2],[3,4]] and B = [[2,0],[1,2]], then AB equals:
Answer
AB = [[4,4],[10,8]]. Row 1 of AB: (1×2 + 2×1, 1×0 + 2×2) = (4, 4). Row 2 of AB: (3×2 + 4×1, 3×0 + 4×2) = (10, 8). So AB = [[4,4],[10,8]].
Assertion (A): For any square matrix A, A + A' is always symmetric. Reason (R): (A+A')' = A' + (A')' = A' + A.
Answer
Both A and R are true and R is the correct explanation of A. Reason R correctly expands (A+A')' using (X+Y)' = X'+Y' and (A')' = A, giving A' + A. Since A' + A = A + A', this shows (A+A')' = A+A', which is exactly the condition for A+A' to be symmetric — proving Assertion A and matching it directly.
Find x and y if [[x+y, 2], [5, y]] = [[6, 2], [5, 3]].
Answer
Two matrices are equal only when corresponding entries match. Comparing the (2,2) entries: y = 3. Comparing the (1,1) entries: x + y = 6, so x = 6 − 3 = 3. Hence x = 3 and y = 3.
If A = [[3,-2],[4,1]], verify that A + A' is a symmetric matrix.
Answer
First find A' by swapping rows and columns: A' = [[3,4],[-2,1]]. Add: A + A' = [[3+3, -2+4], [4-2, 1+1]] = [[6,2],[2,2]]. A matrix is symmetric if it equals its own transpose. The transpose of [[6,2],[2,2]] is [[6,2],[2,2]] itself, since the off-diagonal entries (both 2) are equal. Hence A + A' is symmetric.
If A = [[1,2],[2,1]] and I is the 2×2 identity matrix, show that A² − 2A − 3I = O (the zero matrix).
Answer
First compute A²: A² = [[1×1+2×2, 1×2+2×1], [2×1+1×2, 2×2+1×1]] = [[5,4],[4,5]]. Next, 2A = [[2,4],[4,2]] and 3I = [[3,0],[0,3]]. Now A² − 2A − 3I = [[5-2-3, 4-4-0], [4-4-0, 5-2-3]] = [[0,0],[0,0]]. Since every entry is 0, A² − 2A − 3I = O, as required.
Express the matrix A = [[3,5],[1,-1]] as the sum of a symmetric matrix and a skew-symmetric matrix.
Answer
Every square matrix A can be written as A = P + Q, where P = (A+A')/2 is symmetric and Q = (A−A')/2 is skew-symmetric. Here A' = [[3,1],[5,-1]]. A + A' = [[3+3, 5+1], [1+5, -1-1]] = [[6,6],[6,-2]], so P = (1/2)[[6,6],[6,-2]] = [[3,3],[3,-1]]. A − A' = [[3-3, 5-1], [1-5, -1+1]] = [[0,4],[-4,0]], so Q = (1/2)[[0,4],[-4,0]] = [[0,2],[-2,0]]. Check: P is symmetric (equal off-diagonal entries, 3 and 3), and Q is skew-symmetric (entries 2 and −2 with zero diagonal). P + Q = [[3+0, 3+2], [3-2, -1+0]] = [[3,5],[1,-1]] = A, confirming the decomposition A = P + Q.
Using elementary row operations, find the inverse of A = [[2,1],[1,1]].
Answer
Write the augmented matrix [A | I]: [[2,1 | 1,0], [1,1 | 0,1]]. Swap rows: R1↔R2 gives [[1,1 | 0,1], [2,1 | 1,0]]. Apply R2 → R2 − 2R1: [[1,1 | 0,1], [0,-1 | 1,-2]]. Apply R2 → −R2: [[1,1 | 0,1], [0,1 | -1,2]]. Apply R1 → R1 − R2: [[1,0 | 1,-1], [0,1 | -1,2]]. The left block is now I, so the right block is the inverse: A⁻¹ = [[1,-1],[-1,2]]. Check: A·A⁻¹ = [[2,1],[1,1]]·[[1,-1],[-1,2]] = [[2-1, -2+2], [1-1, -1+2]] = [[1,0],[0,1]] = I. Correct.
Read the following and answer the questions that follow: A stationery store sells notebooks and pens from two outlets. In week 1, matrix A = [[40,25],[30,20]] gives the units sold, where rows represent Store P and Store Q and columns represent notebooks and pens. In week 2, matrix B = [[35,30],[25,15]] gives the same information. (a) Find the total units sold over both weeks, A + B. (b) Each notebook costs ₹20 and each pen costs ₹10. Write the price column matrix C. (c) Using matrix multiplication, find the week-1 revenue for each store, A×C. (d) State the order of the revenue matrix found in (c).
Answer
(a) A + B = [[40+35, 25+30], [30+25, 20+15]] = [[75,55],[55,35]] units. (b) The price column matrix is C = [[20],[10]], listing the price per notebook and per pen. (c) A×C: Store P revenue = 40×20 + 25×10 = 800 + 250 = 1050. Store Q revenue = 30×20 + 20×10 = 600 + 200 = 800. So A×C = [[1050],[800]] rupees. (d) A is 2×2 and C is 2×1, so A×C has order 2×1.
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